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12a^2-43a+25=0
a = 12; b = -43; c = +25;
Δ = b2-4ac
Δ = -432-4·12·25
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-\sqrt{649}}{2*12}=\frac{43-\sqrt{649}}{24} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+\sqrt{649}}{2*12}=\frac{43+\sqrt{649}}{24} $
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